EMCET Model Question paper & Answers

EMCET Model Question and Answers


1. Algebra

Q1: If x+2y=6x + 2y = 6 and 2xy=72x - y = 7, find the values of xx and yy.

Answer: Solve the system of equations:

x+2y=6(1)x + 2y = 6 \quad \text{(1)} 2xy=7(2)2x - y = 7 \quad \text{(2)}

Multiply equation (1) by 2:

2x+4y=12(3)2x + 4y = 12 \quad \text{(3)}

Now subtract equation (2) from equation (3):

(2x+4y)(2xy)=127(2x + 4y) - (2x - y) = 12 - 7 5y=55y = 5 y=1y = 1

Substitute y=1y = 1 into equation (1):

x+2(1)=6x + 2(1) = 6 x=4x = 4

Thus, x=4x = 4 and y=1y = 1.


2. Trigonometry

Q2: Find the value of sin30\sin 30^\circ.

Answer:

sin30=12\sin 30^\circ = \frac{1}{2}

3. Coordinate Geometry

Q3: Find the distance between the points A(3,4)A(3, 4) and B(6,8)B(6, 8).

Answer: Using the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substitute the values of the coordinates:

d=(63)2+(84)2d = \sqrt{(6 - 3)^2 + (8 - 4)^2} d=32+42=9+16=25=5d = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5

Thus, the distance is 5 units.


4. Calculus

Q4: Find the derivative of f(x)=3x25x+2f(x) = 3x^2 - 5x + 2.

Answer: Using the power rule for differentiation:

f(x)=6x5f'(x) = 6x - 5

5. Probability

Q5: If a die is rolled, what is the probability of getting a number greater than 4?

Answer: The numbers greater than 4 on a die are 5 and 6, so there are 2 favorable outcomes.

The total number of possible outcomes on a die is 6.

Thus, the probability is:

P(greater than 4)=26=13P(\text{greater than 4}) = \frac{2}{6} = \frac{1}{3}

6. Quadratic Equations

Q6: Solve the quadratic equation x24x5=0x^2 - 4x - 5 = 0.

Answer: The equation is in the form ax2+bx+c=0ax^2 + bx + c = 0. Using the quadratic formula:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Here, a=1a = 1, b=4b = -4, and c=5c = -5:

x=(4)±(4)24(1)(5)2(1)x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(1)(-5)}}{2(1)} x=4±16+202x = \frac{4 \pm \sqrt{16 + 20}}{2} x=4±362x = \frac{4 \pm \sqrt{36}}{2} x=4±62x = \frac{4 \pm 6}{2}

Thus, the solutions are:

x=4+62=5orx=462=1x = \frac{4 + 6}{2} = 5 \quad \text{or} \quad x = \frac{4 - 6}{2} = -1

Thus, x=5x = 5 or x=1x = -1.


7. Set Theory

Q7: If A={1,2,3,4}A = \{1, 2, 3, 4\} and B={3,4,5,6}B = \{3, 4, 5, 6\}, find ABA \cup B (the union of AA and BB).

Answer: The union of sets AA and BB is the set of all elements that are in either AA or BB, or in both.

AB={1,2,3,4,5,6}A \cup B = \{1, 2, 3, 4, 5, 6\}

8. Matrices

Q8: Find the determinant of the matrix (2345)\begin{pmatrix} 2 & 3 \\ 4 & 5 \end{pmatrix}.

Answer: The determinant of a 2x2 matrix (abcd)\begin{pmatrix} a & b \\ c & d \end{pmatrix} is given by:

det=adbc\text{det} = ad - bc

For the matrix (2345)\begin{pmatrix} 2 & 3 \\ 4 & 5 \end{pmatrix}:

det=(2)(5)(3)(4)=1012=2\text{det} = (2)(5) - (3)(4) = 10 - 12 = -2

Thus, the determinant is 2-2.


9. Progressions

Q9: Find the sum of the first 10 terms of an arithmetic progression where the first term a=2a = 2 and the common difference d=3d = 3.

Answer: The formula for the sum of the first nn terms of an arithmetic progression is:

Sn=n2[2a+(n1)d]S_n = \frac{n}{2} [2a + (n-1)d]

Substituting the values:

S10=102[2(2)+(101)(3)]S_{10} = \frac{10}{2} [2(2) + (10-1)(3)] S10=5[4+27]=5×31=155S_{10} = 5 [4 + 27] = 5 \times 31 = 155

Thus, the sum of the first 10 terms is 155.


10. Logarithms

Q10: Solve log232=x\log_2 32 = x.

Answer: We know that 32=2532 = 2^5, so:

log232=5\log_2 32 = 5

Thus, x=5x = 5.


11. Limits

Q11: Find the limit limx0sinxx\lim_{x \to 0} \frac{\sin x}{x}.

Answer: The limit of sinxx\frac{\sin x}{x} as x0x \to 0 is a standard limit, and its value is:

limx0sinxx=1\lim_{x \to 0} \frac{\sin x}{x} = 1

Would you like me to continue with more questions and answers? Feel free to let me know if you'd like to focus on specific topics or if you'd prefer additional questions!

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